电路分析吧 关注:4,191贴子:23,414
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IP属地:浙江来自Android客户端1楼2022-12-10 07:54回复
    [U+1A(1H+2H)]/[(1H+2H)s+1Ω]+[U-2A(1H+2H)]/[(1H+2H)s+1Ω]+(U-1)/(-s+1)=0
    => u2(s)=(U+1(1+2))/((1+2)s+1) = (3s+13)/(3s²+10s+3)
    => u2(t) =1.5e^(-t/3)-0.5e^(-3t)


    IP属地:广西3楼2022-12-23 16:34
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