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IP属地:江西来自iPhone客户端1楼2023-05-05 13:52回复
    忍不住了,开导!🥵🥵🥵
    (sinx)' = cosx
    (cosx)' = - sinx
    (tanx)'=1/(cosx)^2=(secx)^2=1+(tanx)^2
    -(cotx)'=1/(sinx)^2=(cscx)^2=1+(cotx)^2
    (secx)'=tanx·secx
    (cscx)'=-cotx·cscx
    (arcsinx)'=1/(1-x^2)^1/2
    (arccosx)'=-1/(1-x^2)^1/2
    (arctanx)'=1/(1+x^2)
    (arccotx)'=-1/(1+x^2)
    (arcsecx)'=1/(|x|(x^2-1)^1/2) (arccscx)'=-1/(|x|(x^2-1)^1/2) ④(sinhx)'=coshx
    (coshx)'=sinhx
    (tanhx)'=1/(coshx)^2=(sechx)^2 (coth)'=-1/(sinhx)^2=-(cschx)^2 (sechx)'=-tanhx·sechx (cschx)'=-cothx·cschx
    (arsinhx)'=1/(x^2+1)^1/2
    (arcoshx)'=1/(x^2-1)^1/2
    (artanhx)'=1/(x^2-1) (|x|1)
    (arsechx)'=1/(x(1-x^2)^1/2)
    (arcschx)'=1/(x(1+x^2)^1/2) 已经全部导出来一滴都没有了


    IP属地:四川来自Android客户端2楼2023-05-05 13:58
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